# 30 seconds of python

Back to Home#### bifurcate

listintermediateSplits values into two groups.
If an element in `filter`

is `True`

, the corresponding element in the collection belongs to the first group; otherwise, it belongs to the second group.

Use list comprehension and `enumerate()`

to add elements to groups, based on `filter`

.

def bifurcate(lst, filter): return [ [x for i,x in enumerate(lst) if filter[i] == True], [x for i,x in enumerate(lst) if filter[i] == False] ]